1+B^2=2B

Solution for 1+B^2=2B equation:

Simplifying
1 + B2 = 2B

Solving
1 + B2 = 2B

Solving for variable 'B'.

Reorder the terms:
1 + -2B + B2 = 2B + -2B

Combine like terms: 2B + -2B = 0
1 + -2B + B2 = 0

Factor a trinomial.
(1 + -1B)(1 + -1B) = 0

Subproblem 1
Set the factor '(1 + -1B)' equal to zero and attempt to solve:

Simplifying
1 + -1B = 0

Solving
1 + -1B = 0

Move all terms containing B to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1B = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1B = 0 + -1
-1B = 0 + -1

Combine like terms: 0 + -1 = -1
-1B = -1

Divide each side by '-1'.
B = 1

Simplifying
B = 1
Subproblem 2
Set the factor '(1 + -1B)' equal to zero and attempt to solve:

Simplifying
1 + -1B = 0

Solving
1 + -1B = 0

Move all terms containing B to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1B = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1B = 0 + -1
-1B = 0 + -1

Combine like terms: 0 + -1 = -1
-1B = -1

Divide each side by '-1'.
B = 1

Simplifying
B = 1
Solution
B = {1, 1}